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3t^2-36t-84=0
a = 3; b = -36; c = -84;
Δ = b2-4ac
Δ = -362-4·3·(-84)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-48}{2*3}=\frac{-12}{6} =-2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+48}{2*3}=\frac{84}{6} =14 $
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